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The extragalactic background radiation, composed of IR and UV photons
$ \gamma_{\rm EBL} $ , accumulated over cosmological time from the radiation of stars and from the re-emission by dust. The free path length of γ-photons with energy$ E_{\gamma0} $ relative to the process$ \gamma+\gamma_{\rm EBL}\to e^+e^- $ is [1]$ D_{\gamma 0}\simeq0.8\left(\frac{E_{\gamma0}}{1\; {\rm{TeV}}}\right)^{-1}\; \rm{Gpc}, $
(1) and the energy of the electron or positron being born is
$ E_e\simeq E_{\gamma0}/2 $ with the threshold$ E_{\gamma0}\simeq250 $ GeV.The
$ e^+ $ or$ e^- $ with initial energy$ E_e $ loses energy due to inverse Compton scattering by photons of relic radiation at the distance [1]$ \lambda_e=\frac{3m_e^2}{4\sigma_T\rho_r E_e}\simeq0.233\left(\frac{E_{\gamma0}}{1\; {\rm{TeV}}}\right)^{-1}\; \rm{Mpc}, $
(2) where
$ m_e $ is the mass of the electron,$ \sigma_T $ is the Compton cross-section, and$ \rho_r $ is the density of relic radiation. This process is accompanied by the emission of the secondary photons, and the relationship between the energy of the primary photon$ E_{\gamma0} $ and the energy of the secondary photon$ E_{\gamma} $ has the form$ E_\gamma=\frac{4E_rE_e^2}{3m_e^2}\simeq0.75\left(\frac{E_{\gamma0}}{1\; {\rm{TeV}}}\right)^2\; \rm{GeV}, $
(3) where the mean energy of the relic radiation photon is
$ E_r=6\times10^{-4} $ eV.The Larmor radius of the
$ e^\pm $ trajectory is$ r_L=\frac{E_e}{eB}\simeq5.4\times10^{-2}\left(\frac{E_{\gamma0}}{1\; {\rm{TeV}}}\right)\left(\frac{B}{10^{-14}\; {\rm{G}}}\right)^{-1}\; \rm{Mpc}, $
(4) and the deflection angle of an electron or positron in a magnetic field [2]
$ \delta\simeq\frac{\lambda_e}{r_L}\simeq4.31\left(\frac{E_{\gamma0}}{1\; {\rm{TeV}}}\right)^{-2}\left(\frac{B}{10^{-14}\; {\rm{G}}}\right)\; {\rm{rad}}, $
(5) where
$ \lambda_e $ is as expressed by (2). It should be noted, however, that the electron emits many photons, and an electromagnetic cascade develops. Losing energy, the electron is deflected at larger angles. Therefore, (5) refers only to the emission of the first most energetic photon and has the meaning of the minimum deflection angle. If$ \lambda_e>l_c $ , the deviation of the trajectory has a diffusive character, and the angle δ cannot be obtained from (5). To illustrate the method, we consider only the most energetic secondary photons that deviate by minimal angles. -
The theory of gravitational lensing is presented, for example, in [31, 32], where, in particular, the equation of the gravitational lens is derived. In this section, we obtain a similar equation for the case when, at a distance of
$ D_{\gamma 0} $ from the source, a gamma photon generates$ e^+e^- $ pairs. The electrons (positrons) of the pairs are deflected in the magnetic field by an angle δ and generate secondary gamma photons via reverse Compton scattering. While the low-energy part of the primary gamma radiation is lensed in the same way as that for the optical and gamma radiation of the blazar, the photons of the secondary gamma radiation follow different trajectories because the$ e^+ $ and$ e^- $ producing them have deflected in the intergalactic magnetic field.Suppose that the distance
$ D_{\gamma 0} $ is less than the distance from the source to the lens$ D_{LS} $ so that the lens deflects the secondary photons. Thus, at the distance$ D_{\gamma 0} $ from the source, there is a break of the beam trajectory at an angle δ (see Fig. 1), which must be considered in the lens equation.Figure 1. Configuration of gravitational lensing considering the rotation of the trajectory at point P by an angle δ due to the deflection of
$ e ^\pm $ in the magnetic field. S is a blazar (source of primary gamma radiation), L is a gravitational lens, and O is an observer registering secondary gamma radiation. The relative vertical scales are increased, though in reality, all the angles shown are small.The angle
$ \hat\alpha $ (all angles are assumed to be small) is the deflection of light passing at a distance$ r_m $ from the point mass M,$ \hat\alpha=\frac{4GM}{c^2r_m}, $
(6) and the Einstein angular radius is expressed as
$ \begin{aligned}[b] \theta_E=&\sqrt{\frac{D_{LS}}{D_{OS}D_{OL}}\frac{4GM}{c^2}} \\ =&1.4\times10^{-5}\left(\frac{1\; {\rm{Gpc}}\times D_{LS}}{D_{OS}D_{OL}}\right)^{1/2}\left(\frac{M}{10^{12}M_\odot}\right)^{1/2}. \end{aligned} $
(7) Then, the reduced deflection angle
$ \alpha=\hat\alpha\frac{D_{LS}}{D_{OS}}=\frac{\theta_E^2}{\theta}. $
(8) The equation of an ordinary gravitational lens is written as
$ \begin{array}{*{20}{l}} \theta=\beta+\alpha. \end{array} $
(9) In our case, the geometry of the path of the light beam includes an additional rotation by the angle δ (see Fig. 1). Therefore, the lens equation takes the following form:
$ \theta=\beta+\alpha+\delta\frac{D_{\gamma 0}}{D_{OS}}. $
(10) For brevity, we denote
$ \tilde\delta=\delta D_{\gamma 0}/D_{OS} $ and rewrite the equation of the lens as$ \begin{array}{*{20}{l}} \theta^2-(\beta+\tilde\delta)\theta-\theta_E^2=0 . \end{array} $
(11) Its solutions (
$ \pm $ correspond to two images)$ \theta_\pm=\frac{\beta+\tilde\delta}{2}\pm\theta_E\sqrt{1+\frac{(\beta+\tilde\delta)^2}{4\theta_E^2}} $
(12) in the limit
$ \tilde\delta=0 $ are reduced to the known solutions of Eq. (9) given in [31]. If the objects are located at cosmological distances, the distances in the above formulas should be understood as cosmological distances that determine the angles [31].Note that (12) includes the sum of
$ \beta+\tilde\delta $ , so the value$ \tilde\delta $ plays the role of an additional angular shift of the gravitational lens from the$ S O $ line of sight. The magnetic field plays a decisive role in the deflection of the beam when$ \tilde\delta\geq\beta $ . According to (5), this condition for the first photon emitted in the process of reverse Compton scattering has the form$ E_{\gamma0}\leq7\left(\frac{\beta}{0.01}\right)^{-1/3} \left(\frac{B}{10^{-14}\; {\rm{G}}} \right)^{1/3}\left(\frac{D_{OS}}{1\; {\rm{Gpc}}} \right)^{-1/3}\; {\rm{TeV}}. $
(13) At high energies, two images of the blazar will be observed in gamma rays at the same angles as in optical observations. If (13) is true, there will actually be no gravitational lensing. The observed image of the blazar will be surrounded by a gamma halo in this case, as shown in [2], and the gravitational lens will distort only a small portion of this halo.
An electron or positron loses energy as photons are emitted and deviates at even greater angles, so the subsequent emitted photons also satisfy the criterion
$ \tilde\delta\geq\beta $ . If the initial photon does not satisfy the$ E_{\gamma0} $ requirement in (13), the initial emitted photons do not satisfy the criterion$ \tilde\delta\geq\beta $ , but the subsequent ones can. Note that, among all the secondary photons, only those photons that were born in the planes passing through the Earth and the lens galaxy reach the observer along the optical path of the lens. At the same time, the blazar itself (the source of primary photons) is no longer obliged to lie in this plane, as it would be in the case of conventional gravitational lensing. Accordingly, when secondary gamma radiation is lensed, the two images will be in the form of two arcs with angular size$ \theta_\pm $ . Electrons and positrons are deflected in opposite directions by angles$ \pm\delta $ , so each of the two images splits into two more parts.The opening angle of the blazar jet has some finite value
$\theta_{\rm jet}\sim3^\circ-5^\circ$ . Therefore, depending on the direction of the jet, only one of the trajectories (primary gamma radiation) of the gravitational lens can enter the jet, or all the rays will pass outside the jet; then, gravitational lensing will not happen.Note that, in the case of weak magnetic fields, the modified equation of the gravitational lens (10) cannot be interpreted as the gravitational lensing of some extended object (cloud
$ e^\pm $ ) arising at a distance of$ D_{\gamma 0} $ from the blazar. This is due to the fact that the direction of the$ e^\pm $ movement and, accordingly, the direction of the secondary photons are important.Let us now consider the case
$ D_{\gamma 0}>D_{LS} $ , when the gravitational lens deflects the primary gamma radiation. The geometry in this case leads to the same equation of the lens (10). Note, however, that in order to fulfill the condition$ D_{\gamma 0}>D_{LS} $ , the lens galaxy should be located very close to the source, and such a configuration is very rare; therefore, we do not consider this case further. -
It should also be considered that
$ e^+ $ and$ e^- $ in each of the two optical paths are deflected by the magnetic field in different directions; therefore, there are four different paths of secondary photons. At the same time, the magnetic field in each of the four regions may be different in magnitude and direction if these regions are separated by a distance exceeding the magnetic field coherence length$ l_c $ . At the$ l_c $ scale, the magnetic field changes by the amount of$ \Delta B\sim B $ , so the angle of deflection also varies greatly$ \Delta\delta\sim\delta $ . Moreover, even if the specified regions in each of the "+" and "–" paths are located closer than$ l_c $ , the distance between "+" and "–" pairs may exceed$ l_c $ . This poses the problem of considering various cases with different ratios of distances between the$ e^+ $ and$ e^- $ origin locations and$ l_c $ , as well as different variants of random variables B in the case when the origin locations are spaced further than$ l_c $ .Let us find the distance L (the length of the segment PN in Fig. 1) of the
$ e^+e^- $ origin locations from the line of sight$S O$ . From the geometry of ray propagation, one has$ \begin{array}{*{20}{l}} L_\pm=D_{\gamma 0}(\hat\alpha+\beta-\theta_\pm+\delta). \end{array} $
(14) Depending on the numerical values,
$ L_\pm $ can either be greater or less than the coherence length$ l_c $ . The distance between the$ e^+ $ and$ e^- $ origin locations in one path "+" is$ \begin{array}{*{20}{l}} \Delta L_+=L_+^{(1)}-L_+^{(2)}, \end{array} $
(15) where
$ e^+ $ and$ e^- $ are denoted by the indices "(1)" and "(2)," respectively. In the case of$ D_{\gamma 0}\ll D_{OS} $ , taking into account (14), the value (15) can be estimated as$ \Delta L_+\sim 2\delta D_{\gamma 0}=0.6\left(\frac{E_{\gamma0}}{5\; {\rm{TeV}}}\right)^{-3}\left(\frac{B}{10^{-14}\; {\rm{G}}}\right)\; {\rm{Mpc}}. $
(16) If
$ B\gg10^{-14} $ G, in most cases, at the energies we consider, the value of (16), and even more so (14), exceeds 1 Mpc. -
Let us consider the question of the time delay between the signals that have propagated in two ways around a gravitational lens. Calculating the geometric delay (between the cases of the presence and absence of a lens) in the presence of an additional deviation by the angle δ instead of the Eq. (3.36) in [31] now gives
$ \delta t_{\rm geom}=\frac{D_{OS}D_{OL}}{2cD_{LS}}\left[(\theta-\beta)^2-\tilde\delta(\theta-\beta)\right]. $
(17) It should be noted that, for
$ e^+ $ and$ e^- $ , angle$ \tilde\delta $ has opposite signs, so there will be four components in the received signal that come earlier and later than in case of the$ e^\pm $ absence.The gravitational time delay (Shapiro delay) was calculated, e.g., in [33] as
$ \delta t_{grav}=\frac{2GM}{c^3}\left(\frac{r-r_0}{r+r_0}\right)^{1/2}+\frac{2GM}{c^3}\ln\left(\frac{r+\sqrt{r^2-r_0^2}}{r_0}\right), $
(18) where, in the point lens approximation,
$ r_0 $ is the minimum distance of the trajectory to the lens, r is the distance of the observer from the lens, M is the mass of the lens galaxy, and G is the gravitational constant. In our case, one can evaluate$ r_0/r\simeq D_{OL}\theta $ . The full time delay$\delta t(\theta,\tilde\delta)=\delta t_{\rm geom}+\delta t_{\rm grav}$ depends on θ ($ \theta=\theta_\pm $ for two paths) and$ \tilde\delta $ .Consider the case when
$ L_++L_-<l_c $ , i.e., the magnetic field for all four regions of$ e^+ $ and$ e^- $ is the same. The difference in the signal travel time along two paths is$ \begin{array}{*{20}{l}} \Delta t(\tilde\delta)=\delta t(\theta_+,\tilde\delta)-\delta t(\theta_-,\tilde\delta). \end{array} $
(19) With the above equations, one has
$ \begin{aligned}[b] \Delta t(\tilde\delta)=&\frac{2GM}{c^3}\ln\left|\frac{\theta_+}{\theta_-}\right| \\ &+\theta_E\sqrt{1+\frac{(\beta+\tilde\delta)^2}{4\theta_E^2}}\left(\frac{4GM}{c^3}-\frac{D_{OS}D_{OL}}{2cD_{LS}}\beta\right). \end{aligned} $
(20) When observing the lensing of the blazar in the radio range, there will be no correction from
$ \tilde\delta $ ; therefore, the relative shift of the difference in the course of the rays between the gamma and radio ranges is$ \Delta=\frac{\Delta t^{\gamma}-\Delta t^{\rm radio}}{\Delta t^{\rm radio}}=\frac{\Delta t(\tilde\delta)-\Delta t(\tilde\delta=0)}{\Delta t(\tilde\delta=0)}. $
(21) In the case of the blazar B0218+357 discussed below, the gravitational time delay turns out to be more important than the geometric one.
If
$ \tilde\delta\sim\beta $ , the shift of the time arrival difference of the signals can be comparable to the time difference itself$ \Delta\sim1 $ . Moreover, in the case of$ \tilde\delta\leq\beta $ , the signal in the secondary gamma radiation will not be averaged over long periods, and flash activity in the radio range and at high energies can be compared in the same case of gravitational lensing. Then, based on the delay of the signals, it will be possible to draw a conclusion about intergalactic magnetic fields. This method differs from the method proposed in [6] for searching for echo signals between primary and secondary gamma radiation from blazars without gravitational lensing. The problem lies only in separating the secondary gamma radiation against the background of the primary one, which can also be variable. Such separation can be performed according to the Fourier analysis of time profiles. The primary gamma radiation will be lensed in the same way as the radio emission of the blazar, and the secondary radiation will have a different time delay depending on the energy.More precisely, we should disregard the delay of the signal and consider the broadening or splitting of the lensed pulse into two parts because
$ \tilde\delta $ has two opposite sign values for$ e^+ $ and$ e^- $ . However, one of the images is usually more strongly enhanced by the gravitational lens and will prevail, so the broadening of the pulse will be asymmetric and look like an additional time shift. In the case when$ l_c $ is less than the distance between the origin locations of$ e^+ $ and$ e^- $ , several different options are possible, as explained earlier.We apply the formalism developed in this Section to the case of gamma-lensing of the B0218+357 blazar. In the study reported in [22], it was found that the delay between the lensed gamma signals is
$ 11.46\pm0.16 $ days, which is$ \sim1 $ day more than the delay between radio signals. Note, however, that in [34], a different result was obtained with less or no delay. If an actual difference of$ \sim1 $ day between the delay times exists, due to the formation of$ e^\pm $ , then$ \Delta\sim0.1 $ . The configuration of gravitational lensing was discussed in [35−37]. The blazar B0218+357 is at$ z=0.944\pm0.002 $ , and the lens is at$ z=0.6847 $ . It follows that$ D_{LO}\approx1.48 $ Gpc and$ D_{SO}\approx1.65 $ Gpc. The Einstein radius is$ \theta_E\simeq0.1672\pm0.0006'' $ . The angular distance between the images is$ 0.3344'' $ . Thus, we obtain$ \beta\simeq0.0035'' $ , and from the numerical solution of (21), we get$ \tilde\delta\simeq0.00034'' $ . With this value, according to the formulas of the Sec. II,$ B>2\times10^{-17}\left(\frac{E_{\gamma}}{100\; {\rm{GeV}}}\right)^{3/2}\; {\rm{G}}, $
(22) where
$ E_{\gamma} $ is the observed energy. Since Fermi-LAT performed observations at energies$ E_{\gamma}>100 $ MeV, we find that$ B>2\times10^{-20} $ G. The MAGIC telescope system observed lensing events at$ E_{\gamma}> $ 100 GeV [29]. According to (22), this gives$ B>2\times10^{-17} $ G, which is comparable in order of magnitude to the constraints resulting from the absence of a gamma halo [1]. Therefore, in the case of B0218+357, it is not possible to obtain useful constraints due to the large distances to the blazar and lens galaxy. The observation of other cases of lensing may provide more favorable opportunities to find or constrain B.Note that, in the energy regions under consideration, there must be a contribution from both primary and secondary gamma radiation, the separation of which is a difficult task. Secondary radiation can make a noticeable contribution to the delayed signal if the flare activity of the blazar occurs mainly at the highest energies of
$ \sim1-100 $ TeV since photons with such energies can produce cascades and secondary photons available for observations. If the primary radiation is also highly variable, the flashes in the secondary radiation will be blurred, and it will be challenging to notice the specified shift by$ \sim1 $ day. -
Let us fix a small energy interval from
$ E_{\gamma0} $ to$E_{\gamma0}+{\rm d}E_{\gamma0}$ . The angle δ in Fig. 1 depends on$ E_{\gamma0} $ , so the interval$ E_{\gamma0} $ to$E_{\gamma0}+{\rm d}E_{\gamma0}$ corresponds to a certain interval of angles from ψ to$\psi+{\rm d}\psi$ . The amount of energy recorded in this interval depends on the solid angle corresponding to the interval from ψ to$\psi+{\rm d}\psi$ . Simultaneously, it is necessary to recalculate the energy of the observed secondary photons according to Eq. (3).From the geometry of the beam, we obtain
$ \begin{array}{*{20}{l}} \psi=\hat\alpha+\beta+\delta-\theta. \end{array} $
(23) If
$ D_{\gamma 0}=\lambda/E $ and$ \delta=\varkappa B/E^2 $ , according to (1) and (5), the differential amount of the observed energy is proportional to the following value:$ \begin{aligned}[b] \frac{{\rm d}\psi_\pm}{{\rm d}E_{\gamma0}}=&\frac{\varkappa B}{E_{\gamma0}^3} \Bigg[\frac{3\lambda}{2E_{\gamma0}D_{OS}}\\&\times\left( 1+\frac{4\theta_E^2D_{OS}}{D_{LS}\left(\beta+\tilde\delta\pm\sqrt{4\theta_E^2+(\beta+\tilde\delta)^2}\right)} \right) \\ &\left.\times \left(1\pm\frac{\beta+\tilde\delta}{\sqrt{4\theta_E^2+(\beta+\tilde\delta)^2}}\right)-2\right]. \end{aligned} $
(24) In the absence of a gravitational lens, only the effect of the cascade gamma radiation gives
$ \frac{{\rm d}\psi}{{\rm d}E_{\gamma0}}=\frac{\varkappa B}{E_{\gamma0}^3}\left[\frac{3\lambda}{E_{\gamma0}D_{OS}}-2\right]. $
(25) If the initial blazar spectrum has a power-law form
$ \Phi(E)=\frac{{\rm d}N}{{\rm d}E}\propto E^{-\Gamma}, $
(26) where usually
$ \Gamma\simeq1.5-1.8 $ [13], after gravitational lensing, it is converted to$\propto({\rm d}\psi/{\rm d}E)E^{-\Gamma}$ . Based on this change in the spectrum compared to the typical spectra of blazars, it could be concluded that the magnetic field played a significant role in the formation of the lensed image. Thus, in the presence of a gravitational lens, an additional dependence of the recorded amount of secondary gamma radiation energy on the magnetic field B and the photon energy$ E_{\gamma0} $ appears (through$ \tilde\delta $ dependence).We denote the product of the terms in parentheses in (24) by
$ S_\pm^i $ , where the indices$ i=1 $ and$ i=2 $ denote electrons and positrons, respectively. Then it can be shown that$ S_+^1+S_-^1=S_+^2+S_-^2=2+\frac{D_{OS}}{2D_{LS}}=const, $
(27) i.e., in the total signal (if four beams are not resolved by angles), the dependence on energy will not differ much from (25). Note, however, that the opening angle of the blazar jet has a finite value. Therefore, if the optical paths fall into the jet only on one side of the lens, there will be no compensation such as that expressed in (27), and the values of
$ S_+^1+S_+^2 $ or$ S_-^1+S_-^2 $ will depend on the energy. Unfortunately, this effect is very small because the corrections in (24) compared to (25) in typical cases are only$ \sim3 $ %; therefore, one can see only the formation of a gamma halo around the blazar image and the transformation of the spectrum by Eq. (25), as indicated in [2].The best prospects for the selection of the spectrum transformations caused by the lens will appear if it is possible to resolve individual images
$ S_+^1 $ ,$ S_+^2 $ ,$ S_-^1 $ , and$ S_-^2 $ . Although the compensation (27) occurs in the sum of the images, in individual images, the additional dependence on energy is quite strong. For example, Fig. 2 shows the value of$ S_+^2 $ for some typical parameter values.Figure 2. Function
$ S_+^1 $ describing the transformation of the blazar spectrum. The energy of the primary photons$ E_{\gamma0} $ is given in TeV. The graph is given for the parameter values$ D_{OS}/D_{LS}=2 $ ,$ \beta/\theta_E=0.2 $ , and$ D_{OS}=1 $ Gpc and for three values of magnetic field B. -
If a gamma-ray telescope allows one to measure the angular distance between two images
$ \theta_+-\theta_- $ depending on the energy, by fitting the observed theoretical dependence, one can find B. Using (12), we get$ \begin{array}{*{20}{l}} \theta_+-\theta_-=\sqrt{4\theta_E^2+(\beta+\tilde\delta)^2}. \end{array} $
(28) Since the configuration of the gravitational lens will be known from optical and radio observations, β and other characteristics of the lens in (28) will be fixed. Therefore, if fitting allows one to find
$ \tilde\delta $ , from the dependence of$ \tilde\delta $ on B given by Eq. (5) at different photon energies, one can find B. The application of this method is possible only in the future when the angular resolution of gamma-ray telescopes will increase by several orders of magnitude to the level of$ \sim1''$ .If the intergalactic magnetic fields are large enough,
$ e^+e^- $ -pairs have time to deviate at large angles, and their trajectories become entangled. As a result, an extended region appears around the blazar, from which secondary photons are emitted; this region is called pair halo. It emits gamma photons as an extended source. In this case, the gravitational lens can create multiple images of the pair halo and amplify the gamma radiation flux in the same way as it amplifies the optical and radio radiation flux. With a sufficiently high resolution in the gamma range, an observer can see that the optical images of the blazars are surrounded by a gamma halo. If the blazar is sufficiently far, such halos would appear around each of its images. For close blazars, these images would overlap. It is important that the gravitational lens enhances the radiation flow. Therefore, the pair halo invisible without a lens can become visible if there is a galaxy (gravitational lens) on the line of sight.
Strong gravitational lensing of blazar gamma-radiation and intergalactic magnetic fields
- Received Date: 2023-09-07
- Available Online: 2024-01-15
Abstract: The influence of intergalactic magnetic fields on the strong gravitational lensing of blazar secondary gamma radiation is discussed. Currently, two cases of strong gravitational lensing of blazar gamma-radiation are known, where radiation is deflected by galaxies on the line of sight between the blazars and Earth. The magnetic field can affect the movements of electron-positron pairs generated by primary radiation, thereby changing the directions of secondary gamma radiation. It modifies the equation of the gravitational lens and leads to the dependence of the observed signal in the secondary gamma radiation on the energy of photons and magnetic field. Accordingly, it is possible, in principle, to estimate the intergalactic magnetic fields from the time delay of signals, from the angular position of images (for future high-resolution gamma-ray telescopes) or from the shape of the observed energy spectrum. This method is demonstrated by the example of the blazar B0218+357. In this case, however, it is not possible to obtain useful constraints due to the large distances to the blazar and lens galaxy. The result is only a lower limit on the magnetic field