THE BOUND STATES OF A BOSON IN THE FIELD OF KERR-NEWMAN'S NAKED SINGULARITY

  • We discuss bound states of a boson in the field of Kerr-Newman's naked singularity by the spectrum Analysis of the self-conjugate extension of linear differential operators. The results show that the self-conjugate extension of the Hamiltonian of the boson has only discrete spectrum in the interval (—μ,μ). From which we can infer that there are no boson bound states if μ=0. Boson bound states appear when μ≠0.
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  • [1] 刘辽, 《广义相对论讲义》, 下册 p. 170 北京师范大学.[3] 张端明, 李元杰, commun., Theor. Phys.,V4 (1985), 853.[4] Cohen J. M: Powers R. T., Commun. Math. Phys., 86(1982), 69.[5] 章世伟, 苏汝铿, 物理学报, 3(1982), 111.[6] 须重明, 谢光中, 科学通报, 25(1950), 1063.[7] de Felic F, Phys. Rev., D19(1979), 451.
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LI Yuan-Jie. THE BOUND STATES OF A BOSON IN THE FIELD OF KERR-NEWMAN'S NAKED SINGULARITY[J]. Chinese Physics C, 1987, 11(2): 198-201.
LI Yuan-Jie. THE BOUND STATES OF A BOSON IN THE FIELD OF KERR-NEWMAN'S NAKED SINGULARITY[J]. Chinese Physics C, 1987, 11(2): 198-201. shu
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Received: 1900-01-01
Revised: 1900-01-01
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THE BOUND STATES OF A BOSON IN THE FIELD OF KERR-NEWMAN'S NAKED SINGULARITY

    Corresponding author: LI Yuan-Jie,
  • Hua Zhong University of Science and Technology

Abstract: We discuss bound states of a boson in the field of Kerr-Newman's naked singularity by the spectrum Analysis of the self-conjugate extension of linear differential operators. The results show that the self-conjugate extension of the Hamiltonian of the boson has only discrete spectrum in the interval (—μ,μ). From which we can infer that there are no boson bound states if μ=0. Boson bound states appear when μ≠0.

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